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-4.9x^2+18x=0
a = -4.9; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·(-4.9)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*-4.9}=\frac{-36}{-9.8} =3+1.83333333333/2.72222222222 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*-4.9}=\frac{0}{-9.8} =0 $
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